11b^2-10b-6=0

Solution for 11b^2-10b-6=0 equation:

11b^2-10b-6=0

a = 11; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·11·(-6)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{91}}{2*11}=\frac{10-2\sqrt{91}}{22}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{91}}{2*11}=\frac{10+2\sqrt{91}}{22}
$